Question

Answer 1

Thu được hỗn hợp khí Z :H₂(a mol) ; H₂S (b mol)

\(M_Z = 9.2 = 18(g/mol) \Rightarrow \dfrac{2a+ 34b}{a+b} =18(1)\)

Al₂S₃ + 6HCl → 2AlCl₃ + 3H₂S

\(\dfrac{b}{3}\).........................................b.........(mol)

2Al + 6HCl → 2AlCl₃ + 3H₂

\(\dfrac{2a}{3}\)..................................a.....................(mol)

\(n_S = 3n_{Al_2S_3} = b(mol)\\ n_{Al} = 2n_{Al_2S_3} + n_{Al\ dư} = \dfrac{2b}{3} + \dfrac{2a}{3}(mol)\\ \Rightarrow 32b + (\dfrac{2b}{3} + \dfrac{2a}{3}).27 = 10,2(2)\\ (1)(2) \Rightarrow a = b = 0,15\\ \Rightarrow \%m_{Al} =\dfrac{ (\dfrac{2.0,15}{3} + \dfrac{2.0,15}{3}).27}{10,2}.100\%= 52,94\%\)