Question

Answer 1

d, \(\left[{}\begin{matrix}3x+2=0\\-\dfrac{2}{5}x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{2}{3}\\x=7:\left(-\dfrac{2}{5}\right)=\dfrac{-35}{2}\end{matrix}\right.\)

Answer 2

\(\left(3x+2\right)\left(\dfrac{-2}{5}x-7\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x+2=0\\\dfrac{-2}{5}x=7\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{-2}{3}\\x=\dfrac{-35}{2}\end{matrix}\right.\)