Question

Answer 1

1. \(\left|2x-1\right|=\dfrac{3}{2}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-1=-\dfrac{3}{2}\\2x-1=\dfrac{3}{2}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=\dfrac{5}{4}\end{matrix}\right.\)

Thế \(x=-\dfrac{1}{4}\)

\(\Leftrightarrow C=4.-\dfrac{1}{4}+3=2\)

Thế \(x=\dfrac{5}{4}\)

\(\Leftrightarrow C=4.\dfrac{5}{4}+3=8\)

Vậy \(C=2;8\) thỏa mãn điều kiện

2.\(C=-\dfrac{5}{2}\)

\(\Leftrightarrow-\dfrac{5}{2}=4x+3\)

\(\Leftrightarrow-\dfrac{11}{2}=4x\)

\(\Leftrightarrow x=-\dfrac{11}{8}\)