1, Thay x = 4 ta được
\(A=\dfrac{1}{16}.4^4+3.4^2-\dfrac{5}{4}.4+5\)
\(=16+48-5+5=64\)
2, Thay x = 1/2 ; y = -1 ta đc
\(B=\dfrac{\dfrac{1}{8}-\dfrac{4.1}{4}\left(-1\right)+3.1-4}{\dfrac{3.1}{8}-3.1-3\left(-1\right)}=\dfrac{\dfrac{1}{8}}{\dfrac{3}{8}}=\dfrac{1}{8}:\dfrac{3}{8}=\dfrac{1}{3}\)