\(\dfrac{1}{6}+\dfrac{5}{6}+\dfrac{1}{3}=\dfrac{8}{6}=\dfrac{4}{3}\)
\(\dfrac{5}{12}+\dfrac{1}{2}+\dfrac{2}{3}+\dfrac{3}{4}=\dfrac{7}{3}\)
a, \(\dfrac{1}{6}\) + \(\dfrac{5}{6}\) + \(\dfrac{2}{6}\) = \(\dfrac{8}{6}\) = \(\dfrac{4}{3}\)
b, \(\dfrac{5}{12}\) + \(\dfrac{6}{12}\) + \(\dfrac{8}{12}\) + \(\dfrac{9}{12}\) = \(\dfrac{28}{12}\) = \(\dfrac{7}{3}\)