Question

Answer 1

\(11,\dfrac{1}{10}-\dfrac{1}{50}+\dfrac{3}{25}=\dfrac{5}{50}-\dfrac{1}{50}+\dfrac{2}{50}=\dfrac{5-1+2}{50}=\dfrac{6}{50}=\dfrac{3}{25}\)

\(12,\dfrac{3}{10}-\dfrac{1}{20}+\dfrac{-8}{5}=\dfrac{6}{20}-\dfrac{1}{20}+\dfrac{-32}{20}=\dfrac{6-1+\left(-32\right)}{20}=\dfrac{-27}{20}\)