Question

Answer 1

\(5,\dfrac{-3\times7}{1\times7}+\dfrac{-2}{7}=\dfrac{-21}{7}+\dfrac{-2}{7}=\dfrac{-23}{7}\\ 6,\dfrac{12}{9}-\dfrac{4\times9}{1\times9}=\dfrac{12}{9}-\dfrac{36}{9}=\dfrac{-24}{9}=\dfrac{-8}{3}\)

Answer 2

\(5,-3+\dfrac{-2}{7}=\dfrac{-3}{1}+\dfrac{-2}{7}=\dfrac{-21}{7}+\dfrac{-2}{7}=\dfrac{-23}{7}\\ 6,3\dfrac{1}{9}-4=\dfrac{3\cdot9+1}{9}-4=\dfrac{28}{9}-\dfrac{4}{1}=\dfrac{28}{9}-\dfrac{36}{9}=\dfrac{-8}{9}\)