Question

 

Answer 1

Refer:

Answer 2

\(\left|x-2\right|\left(x-1\right)\left(x+1\right)\left(x+2\right)=4\)

<=>\(\left|x-2\right|\left(x^2-1\right)\left(x+2\right)=4\)

<=>\(\left[{}\begin{matrix}\left(x-2\right)\left(x+2\right)\left(x^2-1\right)=4\\-\left(x-2\right)\left(x+2\right)\left(x^2-1\right)=4\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}\left(x^2-4\right)\left(x^2-1\right)=4\\\left(x^2-4\right)\left(x^2-1\right)=-4\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x^4-5x^2+4=4\\x^4-5x^2+4=-4\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x^4-5x^2=0\\x^4-5x^2+8=0\left(vô\right)lí\end{matrix}\right.\)

<=>\(x^2\left(x^2-5\right)=0\)

<=>\(\left[{}\begin{matrix}x=0\\x^2=5\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x=0\\x=\pm\sqrt{5}\end{matrix}\right.\)