Đặt 1/x = a ; 1/y = b
\(\left\{{}\begin{matrix}15a-7b=9\\4a+8b=-5\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}60a-28b=36\\60a+120b=-75\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-148b=111\\a=\dfrac{-5-8b}{4}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}b=-\dfrac{111}{148}=-\dfrac{3}{4}\\a=\dfrac{1}{4}\end{matrix}\right.\)
Theo cách đặt x = -4/3 ; y = 4


