Ta có: \(\left(x-1\right)\left(2x-1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{1}{2}\end{matrix}\right.\)
Thay lần lượt giá trị x vào pt \(mx^2-\left(m+1\right)x+1=0\) ta có: \(\left[{}\begin{matrix}m.1^2-\left(m+1\right).1+1=0\\m.\left(\dfrac{1}{2}\right)^2-\left(m+1\right).\dfrac{1}{2}+1=0\end{matrix}\right.\) \(\Leftrightarrow m=2\)


