Question

Answer 1

thi ak ( có 2 điểm kìa )

Answer 2

ĐKXĐ: \(x\ne2,x\ne5\)

\(\Rightarrow\dfrac{4x+1+6\left(x-5\right)-3\left(x-2\right)}{\left(x-2\right)\left(x-5\right)}=0\)

\(\Rightarrow4x+1+6x-30-3x+6=0\Rightarrow7x=23\Rightarrow x=\dfrac{23}{7}\left(tm\right)\)

Answer 3

\(\dfrac{4x+1}{\left(x-2\right)\left(x-5\right)}+\dfrac{6}{x-2}=\dfrac{3}{x-5}\) (đk: x≠2; 5)

⇔\(\dfrac{4x+1}{\left(x-2\right)\left(x-5\right)}+\dfrac{6}{x-2}-\dfrac{3}{x-5}=0\)

⇔\(\dfrac{4x+1+6x-30-3x+6}{\left(x-2\right)\left(x-5\right)}=0\)

⇔\(7x-23=0\)

⇒ \(x=\dfrac{23}{7}\)(TM)