\(A=\left[\left(-\dfrac{3}{11}\right)+\left(-\dfrac{8}{11}\right)\right]+\left(\dfrac{11}{8}-\dfrac{3}{8}\right)\\ A=-\dfrac{6}{11}+1\\ A=-\dfrac{6}{11}+\dfrac{11}{11}=\dfrac{5}{11}\)
A = (−311)+1118−38+(−811)-311+1118-38+-811
= [(−311)+(−811)]+(1118−38)-311+-811+1118-38
= (−3)+(−8)11+11−318-3+-811+11-318
= −1111+88=−1 + 1 = 0
tham khảo :
A = (-3/11) + 11/8 - 3/8 + (-8/11)
A = [(-3/11) + (-8/11)] + (11/8-3/8)
A = -1 + 1
A = 0
\(A=\left(-\dfrac{3}{11}\right)+\dfrac{11}{8}-\dfrac{3}{8}+\left(-\dfrac{8}{11}\right)\)
\(A=\left(-\dfrac{3}{11}\right)+\dfrac{11}{8}+\left(-\dfrac{3}{8}\right)+\left(-\dfrac{8}{11}\right)\)
\(A=\left[\left(-\dfrac{3}{11}\right)+\left(-\dfrac{8}{11}\right)\right]+\left[\dfrac{11}{8}+\left(-\dfrac{3}{8}\right)\right]\)
\(=\left(-11\right)+11\)
\(=0\)
![[GPS] aaa](https://hoc24.vn/images/avt/avt137005040_256by256.jpg)
`A = (-3/11) + 11/8 - 38 + (-8/11)`
`A = [(-3/11) + (-8/11)] + (11/8 - 3/8)`
`A = (-1) + 1`
`A = 0`
Vậy `A = 0`
