Question

Answer 1

a, \(n_{Cu}=\dfrac{9,033.10^{23}}{6.10^{23}}=1,5055\left(mol\right)\Rightarrow m_{Cu}=1,5055.64=96,352\left(g\right)\)

b, \(n_{NO_2}=\dfrac{4,5165.10^{23}}{6.10^{23}}=0,75275\left(mol\right)\Rightarrow m_{NO_2}=0,75275.46=34,6265\left(g\right)\)

c, \(n_{H_2S}=\dfrac{13,44}{22,4}=0,6\left(mol\right)\Rightarrow m_{H_2S}=0,6.34=20,4\left(g\right)\)

d,  \(n_{N_2}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\Rightarrow m_{N_2}=1,5.28=42\left(g\right)\)