a, A = \(\dfrac{3}{2}.\dfrac{4}{3}.\dfrac{5}{4}...\dfrac{100}{99}=\dfrac{100}{2}=50\)
b, \(B=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}...\dfrac{99}{100}=\dfrac{1}{100}\)
c, \(C=\dfrac{-1\left(-2\right)\left(-3\right)...\left(-99\right)}{2.3.4...100}=-\dfrac{1}{100}\)
d, \(D=\dfrac{1.2.2.3.3...99.99}{1.2.2.3.3...99.100}=\dfrac{99}{100}\)
