\(a,\) \(\dfrac{3x-2}{5}+\dfrac{5x-1}{3}=\dfrac{4-3x}{15}\)
\(\Leftrightarrow\dfrac{3\left(3x-2\right)}{15}+\dfrac{5.\left(5x-1\right)}{15}=\dfrac{4-3x}{15}\\ \Leftrightarrow9x-6+25x-5=4-3x\)
\(\Leftrightarrow9x+25x+3x=4+6+5\\ \Leftrightarrow37x=15\\ \Leftrightarrow x=\dfrac{15}{37}\)
\(Vậy.S=\left\{\dfrac{15}{37}\right\}\)
\(b,\) \(\Leftrightarrow\dfrac{3\left(5x+1\right)}{6}-\dfrac{6x}{6}-\dfrac{12}{6}=\dfrac{2\left(x+4\right)}{6}\)
\(\Leftrightarrow15x+3-6x-12=2x+8\\ \Leftrightarrow15x-6x-2x=8-3+12\)
\(\Leftrightarrow7x=17\\ \Leftrightarrow x=\dfrac{17}{7}\)
\(Vậy.S=\left\{\dfrac{17}{7}\right\}\)