\(\dfrac{AE}{ED}=\dfrac{CQ}{BQ}=\dfrac{1}{2}\)
Xét tam giác ADC có:
\(\dfrac{AE}{ED}=\dfrac{CP}{PD}\)(định lí Ta-lét)
=>\(\dfrac{AE}{ED}=\dfrac{CP}{PD}=\dfrac{CQ}{BQ}\)
Xét tam giác BCD có:
\(\dfrac{CP}{PD}=\dfrac{CQ}{BQ}\)(cmt)
=>PQ//BD (định lí Ta-lét đảo)


