\(n_{CH_4}=\dfrac{m}{M}=\dfrac{3,2}{16}=0,2\left(mol\right)\\ V_{CH_4\left(đktc\right)}=n.22,4=0,2.22,4=4,48\left(l\right)\)
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\(n_{CH_4}=\dfrac{m}{M}=\dfrac{3,2}{16}=0,2\left(mol\right)\\ V_{CH_4\left(đktc\right)}=n.22,4=0,2.22,4=4,48\left(l\right)\)