Question

Answer 1

Câu 10: C

Câu 11: B

Câu 12: A

Answer 2

10:C

11:B

12:A

Answer 3

10.C

11.

\(M_{SO_3}=32+48=80\left(DvC\right)\\ \%S=\dfrac{32}{80}.100\%=40\%\)

=> Chọn B

12.

\(M_{CO_2}=12+16.2=44\left(DvC\right)\\ \%O=\dfrac{16.2}{44}.100\%=72\%\)

\(M_{FeO}=56+16=72\left(DvC\right)\\ \%O=\dfrac{16}{72}.100\%=22\%\)

\(M_{SO_2}=32+16.2=64\left(DvC\right)\\ \%O=\dfrac{16.2}{64}.100\%=50\%\)

\(M_{Al_2O_3}=27.2+16.3=102\left(DvC\right)\\ \%O=\dfrac{16.3}{102}.100\%=47\%\)

=> Chọn A

 

Answer 4

1.C

2.B

3.A