Câu 4:
ZnO
\(\%m_{Zn}=\dfrac{65.100\%}{81}=80,25\%\)
\(\%m_O=100\%-80,25\%=19,75\%\)
CaCO3
\(\%m_{Ca}=\dfrac{40.100\%}{100}=40\%\)
\(\%m_C=\dfrac{12.100\%}{100}=12\%\)
\(\%m_O=100\%-40\%-12\%=48\%\)
MgCl2
\(\%m_{Mg}=\dfrac{24.100\%}{95}=25,26\%\)
\(\%m_{Cl}=100\%-25,26\%=74,74\%\)
P2O5
\(\%m_P=\dfrac{62.100\%}{142}=43,66\%\\ \%m_O=100\%-43,66\%=56,34\%\)
Ca(OH)2
\(\%m_{Ca}=\dfrac{40.100\%}{74}=54,05\%\\ \%m_O=\dfrac{32.100\%}{74}=6,18\%\\ \%m_H=100\%-54,05\%-6,18\%=39,77\%\)
C4:
ZnO:
\(\%Zn=\dfrac{65.100}{81}=80,2\%\)
\(\%O=100-80,2=19,8\%\)
CaCO3
\(\%Ca=\dfrac{40.100}{100}=40\%\)
\(\%C=\dfrac{12.100}{100}=12\%\)
\(\%O=100-40-12=48\%\)
MgCl2:
\(\%Mg=\dfrac{24.100}{95}=25,3\%\)
\(\%Cl=100-25,3=74,7\%\)
P2O5:
\(\%P=\dfrac{31.2.100}{142}=43,7\%\)
\(\%O=100-43,7=56,3\%\)
Ca(OH)2:
\(\%Ca=\dfrac{40.100}{74}=54\%\)
\(\%O=\dfrac{16.2.100}{74}=43,2\%\)
\(\%H=100-54-43,2=2,8\%\)
