Question

Answer 1

\(n_{Zn}=\dfrac{6,5}{65}=0,1(Mol)\\ a,PTHH:Zn+2HCl\to ZnCl_2+H_2\\ \Rightarrow n_{ZnCl_2}=n_{Zn}=0,1(mol)\\ \Rightarrow m_{ZnCl_2}=0,1.136=13,6(g)\\ b,n_{H_2}=n_{Zn}=0,1(mol)\\ \Rightarrow V_{H_2}=0,1.22,4=2,24(l)\)

Answer 2

\(PTHH:Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\\ n_{Zn}=\dfrac{m}{M}=\dfrac{6,5}{65}=0,1\left(mol\right)\)

\(Theo.PTHH\Rightarrow n_{Zn}=n_{ZnCl_2}=n_{H_2}=0,1\left(mol\right)\\ \Rightarrow m_{ZnCl_2}=n.M=0,1.136=13,6\left(g\right)\\ \Rightarrow V_{H_2}=n.22,4=0,1.22,4=2,24\left(l\right)\)