Question

Answer 1

Ta có : 

 A = \(\dfrac{7^{10}+1}{7^{10}-1}=\dfrac{\left(7^{10}-1\right)+2}{7^{10}-1}=1+\dfrac{2}{7^{10}-1}\)   

B = \(\dfrac{7^{10}-1}{7^{10}-3}=\dfrac{\left(7^{10}-3\right)+2}{7^{10}-3}=1+\dfrac{2}{7^{10}-3}\)       

Vì \(\dfrac{2}{7^{10}-1}< \dfrac{2}{7^{10}-3}\Rightarrow A< B\)

 

 

 

Answer 2

(7¹⁰ + 1)(7¹⁰ - 3) = (7¹⁰ - 1)²

=> \(\dfrac{7^{10}+1}{7^{10}-1}\) = \(\dfrac{7^{10}-1}{7^{10}-3}\)