\(2^3+3.\left(\dfrac{-1}{2}\right)^2-2^2.4+\left[\left(-2\right)^2:\dfrac{1}{2}\right].8\)
\(=8+3.\dfrac{1}{4}-4.4+\left[4:\dfrac{1}{2}\right].8\)
\(=8+3.\dfrac{1}{4}-4.4+8.8\)
\(=8+\dfrac{3}{4}-16+64\)
\(=\dfrac{35}{4}-16+64\)
\(=\left(\dfrac{-29}{4}\right)+64\)
\(=\dfrac{227}{4}\)