\(n_{CO_2}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\) => \(m_{CO_2}=0,15.44=6,6\left(g\right)\)
\(n_{CO}=\dfrac{5,6}{22,4}=0,25\left(mol\right)\) => \(m_{CO}=0,25.28=7\left(g\right)\)
=> \(\overline{M}_A=\dfrac{6,6+7}{0,15+0,25}=34\left(g/mol\right)\)
