Question

Answer 1

\(=\dfrac{3^{27}}{\left(3^3\right)^5\times3^{16}}=\dfrac{3^{27}}{3^{15}\times3^{16}}=\dfrac{3^{27}}{3^{31}}=\dfrac{1}{3^4}=\dfrac{1}{81}\)

Answer 2

\(\dfrac{3^{27}}{9^5\times3^{16}}=\dfrac{3^{27}}{\left(3^2\right)^5\times3^{16}}=\dfrac{3^{27}}{3^{26}}=3\)