\(a,x=3\Leftrightarrow B=\dfrac{3}{2-3}=-3\\ b,P=A-B=\dfrac{x}{x+2}-\dfrac{3x+6}{x^2-4}+\dfrac{3}{x-2}\\ \Leftrightarrow P=\dfrac{x^2-2x-3x-6+3x+6}{\left(x-2\right)\left(x+2\right)}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\\ c,P=\dfrac{x+2-2}{x+2}=1-\dfrac{2}{x+2}\in Z\\ \Leftrightarrow x+2\inƯ\left(2\right)=\left\{-2;-1;1;2\right\}\\ \Leftrightarrow x\in\left\{-4;-3;-1;0\right\}\left(tm\right)\)
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