Câu hỏi của Xin chào

\(R_{23}=\dfrac{R_2.R_3}{R_2+R_3}=\dfrac{4.4}{4+4}=2\left(\Omega\right)\)\(R_{tđ}=R_1+R_{23}=3+2=5\left(\Omega\right)\)\(I=I_1=I_{23}=\dfrac{U}{R_{tđ}}=\dfrac{10}{5}=2\left(A\right)\)\(U_2=U_3=I_{23}.R_{23}=2.2=4\left(V\right)\)\(\left\{{}\begin{matrix}I_2=\dfrac{U_2}{R_2}=\dfrac{4}{4}=1\left(A\right)\\I_3=\dfrac{U_3}{R_3}=\dfrac{4}{4}=1\left(A\right)\end{matrix}\right.\) Câu trả lời: \(R_{23}=\dfrac{R_2.R_3}{R_2+R_3}=\dfrac{4.4}{4+4}=2\left(\Omega\right)\)\(R_{tđ}=R_1+R_{23}=3+2=5\left(\Omega\right)\)\(I=I_1=I_{23}=\dfrac{U}{R_{tđ}}=\dfrac{10}{5}=2\left(A\right)\)\(U_2=U_3=I_{23}.R_{23}=2.2=4\left(V\right)\)\(\left\{{}\begin{matrix}I_2=\dfrac{U_2}{R_2}=\dfrac{4}{4}=1\left(A\right)\\I_3=\dfrac{U_3}{R_3}=\dfrac{4}{4}=1\left(A\right)\end{matrix}\right.\)