\(\dfrac{x+3}{x^2-1}-\dfrac{x+1}{x^2-x}=\dfrac{x+3}{\left(x-1\right)\left(x+1\right)}+\dfrac{-\left(x+1\right)}{x\left(x-1\right)}=\dfrac{x^2+3x}{x\left(x-1\right)\left(x+1\right)}+\dfrac{-\left(x+1\right)^2}{x\left(x-1\right)\left(x+1\right)}=\dfrac{x^2+3x-x^2-2x-1}{x\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{x\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x\left(x+1\right)}\)


