\(VT=\left(\dfrac{2}{3x}-\dfrac{2}{x+1}\cdot\dfrac{x+1-3x^2-3x}{3x}\right)\cdot\dfrac{x}{x-1}\\ =\left[\dfrac{2}{3x}-\dfrac{2}{x+1}\cdot\dfrac{\left(1-3x\right)\left(x+1\right)}{3x}\right]\cdot\dfrac{x}{x-1}\\ =\left[\dfrac{2}{3x}-\dfrac{2\left(1-3x\right)}{3x}\right]\cdot\dfrac{x}{x-1}=\dfrac{6x}{3x}\cdot\dfrac{x}{x-1}=\dfrac{2x}{x-1}=VP\)

