\(A=\dfrac{-3x-9-x+3+2x}{\left(x-3\right)\left(x+3\right)}=\dfrac{-2\left(x+3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{-2}{x+3}\\ A\in Z\Leftrightarrow x-3\inƯ\left(-2\right)=\left\{-2;-1;1;2\right\}\\ \Leftrightarrow x\in\left\{1;2;4;5\right\}\)

