\(a,A=\dfrac{x+2+x-2+x^2+1}{\left(x-2\right)\left(x+2\right)}=\dfrac{\left(x+1\right)^2}{x^2-4}\\ b,-2< x< 2\Leftrightarrow\left\{{}\begin{matrix}x+2>0\\x-2< 0\end{matrix}\right.\Leftrightarrow x^2-4=\left(x-2\right)\left(x+2\right)< 0\)
Mà \(\left(x+1\right)^2>0\left(x\ne-1\right)\Leftrightarrow A< 0,\forall-2< x< 2;x\ne-1\)


