Question

Answer 1

\(a,\Leftrightarrow\left[{}\begin{matrix}5x+1=\dfrac{6}{7}\\5x+1=-\dfrac{6}{7}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}5x=-\dfrac{1}{7}\\5x=-\dfrac{13}{7}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{35}\\y=-\dfrac{13}{35}\end{matrix}\right.\\ b,\Leftrightarrow\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{4}{9}\right)^3\\ \Leftrightarrow x-\dfrac{2}{3}=\dfrac{4}{9}\Leftrightarrow x=\dfrac{10}{9_{ }}\)