\(VD1:\\ a,=2xy\left(x-3+2y\right)\\ b,=\left(x-1\right)\left(3x+5\right)\\ VD2:\\ a,=x^2\left(x+2y\right)+\left(x+2y\right)=\left(x^2+1\right)\left(x+2y\right)\\ b,=xy\left(x+y\right)-\left(x+y\right)=\left(xy-1\right)\left(x+y\right)\\ VD3:\\ a,=\left(3x-1-4\right)\left(3x-1+4\right)=\left(3x-5\right)\left(3x+3\right)=3\left(x+1\right)\left(3x-5\right)\\ b,=\left(x+y\right)^2-\left(2xy\right)^2=\left(x+y-2xy\right)\left(x+y+2xy\right)\)
Đúng 2
Bình luận (0)
