a) 2NaOH + CO2 --> Na2CO3 + H2O
b) \(n_{CO_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\)
PTHH: 2NaOH + CO2 --> Na2CO3 + H2O
______0,1<-------0,05------->0,05_____________(mol)
=> \(C_{M\left(NaOH\right)}=\dfrac{0,1}{0,1}=1M\)
c) \(m_{Na_2CO_3}=0,05.106=5,3\left(g\right)\)
\(n_{CO_2}=\dfrac{1,12}{22,4}=0,05(mol)\\ a,PTHH:2NaOH+CO_2\to Na_2CO_3+H_2O\\ b,n_{NaOH}=2n_{CO_2}=0,1(mol)\\ \Rightarrow C_{M_{NaOH}}=\dfrac{0,1}{0,1}=1M\\ c,n_{Na_2CO_3}=n_{CO_2}=0,05(mol)\\ \Rightarrow m_{Na_2CO_3}=0,05.106=5,3(g)\)