\(1,=4x^2+4x-15-4x^2-4x-1=-16\\ 2,=x^2+x-12-x^2+10x-25=11x-37\\ 3,=x^2-9x+20+9x^2+12x+4=10x^2+3x+24\\ 4,=\dfrac{2x+8-5x+20-7x+12}{\left(x-4\right)\left(x+4\right)}=\dfrac{-10x+40}{\left(x-4\right)\left(x+4\right)}=\dfrac{-10\left(x-4\right)}{\left(x-4\right)\left(x+4\right)}=\dfrac{-10}{x+4}\\ 5,=\dfrac{3x+15-4x+20+6x+5}{\left(x-5\right)\left(x+5\right)}=\dfrac{5x+40}{\left(x-5\right)\left(x+5\right)}\)
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