\(A=\left(x^2-6xy+9y^2\right)+4\left(x-3y\right)+4+x^2-10x+25+1975\\ A=\left[\left(x-3y\right)^2+4\left(x-3y\right)+4\right]+\left(x-5\right)^2+1975\\ A=\left(x-3y+2\right)^2+\left(x-5\right)^2+1975\ge1975\)
Dấu \("="\Leftrightarrow\left\{{}\begin{matrix}x=5\\x-3y+2=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\\y=\dfrac{7}{3}\end{matrix}\right.\)

