\(a,=\dfrac{11}{12}\cdot\dfrac{16}{33}\cdot\dfrac{3}{5}=\dfrac{4}{15}\\ b,=\dfrac{2^2\cdot5^2\cdot5^3}{2^3\cdot5^4}=\dfrac{5}{2}\\ c,=1+\dfrac{7}{3}-\dfrac{5}{3}=\dfrac{5}{3}\\ d,=5^3\cdot\dfrac{2^4}{5^4}+\dfrac{14}{5}=\dfrac{2^4}{5}+\dfrac{14}{5}=\dfrac{30}{5}=6\)
\(a) \bigg(\dfrac{11}{12} : \dfrac{33}{16}\bigg) . \dfrac{3}{5}\\ = \bigg(\dfrac{11}{12} . \dfrac{16}{33}\bigg) . \dfrac{3}{5}\\ = \dfrac{4}{9} . \dfrac{3}{5}\\ = \dfrac{4}{15}\)
\(b) \dfrac{10^2 . 5^3}{8 . 25^2} \\ = \dfrac{2^2 . 5^2 . 5^3}{2^3 . (5^2)^2}\\ = \dfrac{2^2 . 5^5}{2^3 . 5^4}\\ = \dfrac{5}{2}\)
\(c) (-2013)^0 + \bigg|\dfrac{-7}{3}\bigg| - \sqrt{\dfrac{25}{9}}\\ = 1 + \dfrac{7}{3} - \dfrac{5}{3}\\ = \dfrac{3}{3} + \dfrac{2}{3}\\ = \dfrac{5}{3}\)
\(d) 5^3 . \bigg(\dfrac{-2}{5}\bigg)^4 + \dfrac{14}{5}\\ = 5^3 . \dfrac{(-2)^4}{5^4} + \dfrac{14}{5}\\ = \dfrac{16}{5} + \dfrac{14}{5}\\ = \dfrac{30}{5} = 6\)
