\(a,=\dfrac{x^2+6x+9+3x-9+2x^2-18x}{x\left(x+3\right)\left(x-3\right)}=\dfrac{3x^2-9x}{x\left(x-3\right)\left(x+3\right)}\\ =\dfrac{3x\left(x-3\right)}{x\left(x-3\right)\left(x+3\right)}=\dfrac{3}{x+3}\\ b,=\dfrac{4x^2-8x-3x^2-6x+12x}{\left(x-2\right)\left(x+2\right)}=\dfrac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x+2}\\ c,=\dfrac{2x+4+3x-6-18+5x}{\left(x-2\right)\left(x+2\right)}=\dfrac{10\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{10}{x+2}\)
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