\(a,P=\dfrac{5x-2-3x+6+x^2+2x}{\left(x-2\right)\left(x+2\right)}=\dfrac{\left(x+2\right)^2}{\left(x-2\right)\left(x+2\right)}=\dfrac{x+2}{x-2}\\ b,\left|x+3\right|=5\Leftrightarrow\left[{}\begin{matrix}x=2\left(ktm\right)\\x=-8\left(tm\right)\end{matrix}\right.\\ \Leftrightarrow A=\dfrac{-8+2}{-8-2}=\dfrac{-6}{-10}=\dfrac{3}{5}\\ c,P=\dfrac{x-2+4}{x-2}=1+\dfrac{4}{x-2}\in Z\\ \Leftrightarrow x-2\inƯ\left(4\right)=\left\{-4;-2;-1;1;2;4\right\}\\ \Leftrightarrow x\in\left\{0;1;3;4;6\right\}\)
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