Bài 3:
a. Ta có: \(p'>p''\left(2,02\cdot10^6>0,86\cdot10^5\right)\Rightarrow tau\cdot dang\cdot noi\cdot len\left(cang\cdot len\cdot cao\cdot ap\cdot suat\cdot cang\cdot giam\right)\)
b. \(\left\{{}\begin{matrix}p'=dh'=>h'=\dfrac{p'}{d}=\dfrac{2,02\cdot10^6}{10300}\approx196,12\left(m\right)\\p''=dh''=>h''=\dfrac{p''}{d}=\dfrac{0,86\cdot10^5}{10300}\approx8,3\left(m\right)\end{matrix}\right.\)

