Question

Answer 1

\(1.\)

\(n_{NaOH}=\dfrac{8}{40}=0.2\left(mol\right)\)

\(NaOH+HCl\rightarrow NaCl+H_2O\)

\(0.2............................0.2\)

\(m_{NaCl}=0.2\cdot58.5=11.7\left(g\right)\)

\(2.\)

\(n_{Ca\left(OH\right)_2}=0.2\cdot0.5=0.1\left(mol\right)\)

\(Ca\left(OH\right)_2+2HCl\rightarrow CaCl_2+2H_2O\)

\(0.1.................0.2\)

\(m_{HCl}=0.2\cdot36.5=7.3\left(g\right)\)

\(C\%_{HCl}=a=\dfrac{7.3}{200}\cdot100\%=3.65\%\)

Answer 2

C%HCl=a=7.3200⋅100%=3.65%