\(4P+5O_2\rightarrow P_2O_5\\ P_2O_5+3H_2O\rightarrow2H_3PO_4\\ n_{P_2O_5}=\dfrac{1}{2}n_P=0,2\left(mol\right)\\ n_{H_3PO_4}=2n_{P_2O_5}=0,4\left(mol\right)\\ m_{ddH_3PO_4}=200.1,03=206\left(g\right)\\ \Rightarrow C\%_{H_3PO_4\left(saupu\right)}=\dfrac{0,4.98+206.5\%}{206+0,2.142}.100=21,12\%\)
