\(d,=-\dfrac{1}{15}+\dfrac{4}{9}\cdot\dfrac{3}{8}-\dfrac{5}{6}=-\dfrac{9}{10}+\dfrac{1}{6}=-\dfrac{11}{15}\\ e,=15\cdot\dfrac{1}{25}+\dfrac{1}{5}+2\cdot\dfrac{1}{8}-\dfrac{1}{2}=\dfrac{3}{5}+\dfrac{1}{5}+\dfrac{1}{4}-\dfrac{1}{2}=\dfrac{4}{5}-\dfrac{1}{2}=\dfrac{3}{10}\)