Bài 8:
\(CTTQ:Fe_xO_y\left(x,y:nguy\text{ê}n,d\text{ươ}ng\right)\\ V\text{ì}:\dfrac{m_{Fe}}{m_O}=\dfrac{7}{3}\\ \Leftrightarrow\dfrac{56x}{16y}=\dfrac{7}{3}\\ \Rightarrow\dfrac{x}{y}=\dfrac{7.16}{56.3}=\dfrac{2}{3}\\ \Rightarrow x=2;y=3\\ \Rightarrow CTHH:Fe_2O_3\)
Bài 9:
\(\text{Đ}\text{ặt}:Al_xO_y\left(x,y:nguy\text{ên},d\text{ươ}ng\right)\\ V\text{ì}:\dfrac{m_{Al}}{m_O}=\dfrac{4,5}{4}\\ \Leftrightarrow\dfrac{27x}{16y}=\dfrac{4,5}{4}\\ \Rightarrow\dfrac{x}{y}=\dfrac{4,5.16}{27.4}=\dfrac{2}{3}\\ \Rightarrow x=2;y=3\\ \Rightarrow CTHH:Al_2O_3\)
Bài 8
Có \(\dfrac{m_{Fe}}{m_O}=\dfrac{7}{3}\Rightarrow\dfrac{n_{Fe}}{n_O}.\dfrac{56}{16}=\dfrac{7}{3}\Rightarrow\dfrac{n_{Fe}}{n_O}=\dfrac{7.16}{3.56}=\dfrac{2}{3}\)
=> CT: Fe2O3
Bài 9
\(\dfrac{m_{Al}}{m_O}=\dfrac{4,5}{4}\Rightarrow\dfrac{n_{Al}}{n_O}.\dfrac{27}{16}=\dfrac{4,5}{4}\Rightarrow\dfrac{n_{Al}}{n_O}=\dfrac{2}{3}\)
=> CT: Al2O3
