Ta có:
+ \(U2=U3=3V\left(R2//R3\right)\)
+ \(\left[{}\begin{matrix}I=I1=I23=U1:R1=6:5=1,2A\left(R1ntR23\right)\\\Rightarrow I3=I23-I2=1,2-\left(3:3\right)=0,2A\end{matrix}\right.\)
\(\Rightarrow R3=U3:I3=3:0,2=15\Omega\)
b. \(R3=p3\dfrac{l3}{S3}\Rightarrow l3=\dfrac{R3\cdot S3}{p3}=\dfrac{25\cdot0,2\cdot10^{-6}}{1,10\cdot10^{-6}}=\dfrac{50}{11}\left(m\right)\)


