Question

Answer 1

a.

- \(\%_{Fe_{\left(FeO\right)}}=\dfrac{56}{72}.100\%=77,8\%\)

\(\%_{O_{\left(FeO\right)}}=100\%-77,8\%=22,2\%\)

- \(\%_{Fe_{\left(Fe_2O_3\right)}}=\dfrac{56.2}{160}.100\%=70\%\)

\(\%_{O_{\left(Fe_2O_3\right)}}=100\%-70\%=30\%\)

b.

- \(\%_{C_{\left(CO_2\right)}}=\dfrac{12}{44}.100\%=27,27\%\)

\(\%_{O_{\left(CO_2\right)}}=100\%-27,27\%=72,73\%\)

- \(\%_{S_{\left(SO_3\right)}}=\dfrac{32}{80}.100\%=40\%\)

\(\%_{O_{\left(SO_3\right)}}=100\%-40\%=60\%\)