Question

Answer 1

a. \(R=R1+R2+R3=5+10+15=30\Omega\)

b. \(I=I1=I2=I3=U:R=12:30=0,4A\left(R1ntR2ntR3\right)\)

\(\Rightarrow\left\{{}\begin{matrix}U1=I1\cdot R1=0,4\cdot5=2V\\U2=I2\cdot R2=0,4\cdot10=4V\\U3=I3\cdot R3=0,4\cdot15=6V\end{matrix}\right.\)

Answer 2

\(R=R_1+R_2+R_3=5+10+15=30\Omega\)

\(I_1=I_2=I_3=I_m=\dfrac{U}{R}=\dfrac{12}{30}=0,4A\)

\(U_1=I_1\cdot R_1=0,4\cdot5=2V\)

\(U_2=I_2\cdot R_2=0,4\cdot10=4V\)

\(U_3=I_3\cdot R_3=0,4\cdot15=6V\)