\(1,\dfrac{x}{x^2-1}=\dfrac{2x}{2\left(x-1\right)\left(x+1\right)};\dfrac{3}{2x-2}=\dfrac{3\left(x+1\right)}{2\left(x-1\right)\left(x+1\right)}\\ 2,\dfrac{5x}{3x^2-3}=\dfrac{5x}{3\left(x-1\right)\left(x+1\right)};\dfrac{1}{3\left(x-1\right)}=\dfrac{x+1}{3\left(x-1\right)\left(x+1\right)}\\ 3,\dfrac{-2x}{x^2-1}=\dfrac{-2x\left(2x-5\right)}{\left(x^2-1\right)\left(2x-5\right)};\dfrac{3}{2x-5}=\dfrac{3\left(x^2-1\right)}{\left(x^2-1\right)\left(2x-5\right)}\\ 4,\dfrac{y-12}{6y-36}=\dfrac{y^2-12y}{6y\left(y-6\right)};\dfrac{6}{y^2-6y}=\dfrac{36}{6y\left(y-6\right)}\)
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