\(v,=\dfrac{x^3\left(x-2\right)}{x^3\left(2x-1\right)}=\dfrac{x-2}{2x-1}\\ u,=\dfrac{x^4\left(x^3-1\right)}{\left(x^3-1\right)\left(x^3+1\right)}=\dfrac{x^4}{x^3+1}\\ ư,=\dfrac{\left(x+2-x+2\right)\left(x+2+x-2\right)}{16x}=\dfrac{8x}{16x}=\dfrac{1}{2}\\ x,=\dfrac{0,5\left(49x^2-y^2\right)}{0,5x\left(7x-y\right)}=\dfrac{\left(7x-y\right)\left(7x+y\right)}{x\left(7x-y\right)}=\dfrac{7x+y}{x}\)
\(y,=\dfrac{\left(a^2+2\right)\left(a-3\right)}{a^2+2}=a-3\\ z,=\dfrac{\left(a-b\right)\left(c-d\right)}{\left(a-b\right)\left(a+b\right)\left(c-d\right)\left(c+d\right)}=\dfrac{1}{\left(a+b\right)\left(c+d\right)}\)
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