\(b,=\dfrac{9x+5-5x+7}{2\left(x-1\right)}=\dfrac{4x+12}{2\left(x-1\right)}=\dfrac{2\left(2x+6\right)}{2\left(x-1\right)}=\dfrac{2x+6}{x-1}\\ c,=\dfrac{x-1+2x+3}{3x-4}=\dfrac{3x+2}{3x-4}\\ d,=\dfrac{2x+1+1}{\left(2x-1\right)\left(2x+1\right)}=\dfrac{2x+2}{4x^2-1}\\ e,=\dfrac{1+x^2+5x}{x\left(1-x\right)}\\ f,=\dfrac{2-x-4}{\left(x-4\right)\left(x+4\right)}=\dfrac{-x-2}{\left(x-4\right)\left(x+4\right)}\)
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