\(C=\dfrac{\left(3x-4\right)\left(3x+4\right)}{x\left(3x-4\right)}=\dfrac{3x+4}{x}\\ D=\dfrac{\left(x+2\right)^2}{2\left(x+2\right)}=\dfrac{x+2}{2}\\ E=\dfrac{x\left(2-x\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{-x}{x+2}\\ F=\dfrac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\dfrac{3}{x-2}\\ 6,=\dfrac{\left(x+y\right)^2-4}{\left(x+2\right)^2-y^2}=\dfrac{\left(x+y+2\right)\left(x+y-2\right)}{\left(x+y+2\right)\left(x-y+2\right)}=\dfrac{x+y-2}{x-y+2}\\ 7,=\dfrac{\left(x-y\right)\left(x-1\right)}{\left(x-y\right)\left(y-1\right)}=\dfrac{x-1}{y-1}\\ 8,=\dfrac{2\left(x-y\right)}{\left(x-y\right)^2}=\dfrac{2}{x-y}\\ 9,=\dfrac{x\left(x-y\right)}{\left(y-x\right)\left(y+x\right)}=\dfrac{-x}{x+y}\)
